While performing a thermodynamic experiment a student made the following observations HCl+NaOH→NaCl+H2OΔH=−57.3kJmol−1 CH3COOH+NaOH→CH3COONa+H2OΔH=−55.3kJmol−1The enthalpy of ionization of CH3COOH is calculated by the student _________ kJmol−1 (nearest integer)

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While performing a thermodynamic experiment a student made the following observations
$H C l + N a O H \to N a C l + H_{2} O Δ H = - 57.3 k J m o l^{- 1}$
$C H_{3} C O O H + N a O H \to C H_{3} C O O N a + H_{2} O Δ H = - 55.3 k J m o l^{- 1}$
The enthalpy of ionization of $C H_{3} C O O H$ is calculated by the student _________ $k J m o l^{- 1}$ (nearest integer)

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Detailed Solution

$Δ H_{n e u t r a l i s a t i o n} = - 57.3 k J m o l^{- 1}$

In case of acetic acid

$Δ H = Δ H_{i o n i s a t i o n} + Δ H_{n e u t r a l i s a t i o n}$

$- 55.3 = Δ H_{i o n i s a t i o n} - 57.3$

$Δ H_{i o n i s a t i o n} = 2 K J m o l^{- 1}$

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