While shuffling a pack of playing cards, four are accidently dropped. The probability that the cards that are dropped are one from each suit is

Total number of ways of choosing four cards out of $52$ is ${ }^{52}{C}_4$. The number of ways of choosing one card from each suit is

$\left({ }^{13}{C}_1\right)\left({ }^{13}{C}_1\right)\left({ }^{13}{C}_1\right)\left({ }^{13}{C}_1\right)={13}^4$

Thus, probability of the required event is

$\frac{{13}^4}{{ }^{52}{C}_4}=\frac{13\times 13\times 13\times 13\times 4\times 3\times 2\times 1}{52\times 51\times 50\times 49}=\frac{2197}{20825}$