white phosphorus is a tetra atomic solid $P_{4} (s)$ at room temperature

Find average (P-P) bond enthalpy in kJ/mol
Given:
$\begin{array}{l} △ H_{s u b \lim a t i o n} o f P_{4} (s) = 59 k J / m o l \\ △ H_{A t o m i s a t i o n} o f P_{4} (s) = 1256 k J / m o l \end{array}$

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answer is 201.

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Detailed Solution

$(1265 - 59) \div 6 = 201$
There are 6 P-P bonds in $P_{4}$ molecule. Bond dissociation energy is calculated when reactants and products are in gas phase.

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