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Q.

Why does <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>PH</mi><mn>3</mn></msub></math>have a lower boiling point than <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>NH</mi><mn>3</mn></msub></math>have a lower boiling point than ?


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a

<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>NH</mi><mn>3</mn></msub></math> forms hydrogen bonds.

b

<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>NH</mi><mn>3</mn></msub></math> forms ionic bonds.

c

<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>PH</mi><mn>3</mn></msub></math> forms hydrogen bonds.

d

<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>PH</mi><mn>3</mn></msub></math> forms ionic bonds. 

answer is A.

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Detailed Solution

Concept- Hydrogen bonding occurs between the H atom bonded to the highly electronegative atom (F, O or N) and the electronegative atom of another molecule.
Now, the physical properties (melting point, boiling point, physical state) of substances depend upon the intermolecular forces acting between their molecules.
As per the definition of hydrogen bonding, <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>NH</mi><mn>3</mn></msub></math> is capable to form hydrogen bonds with other molecules of <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>NH</mi><mn>3</mn></msub></math>.
Thus, in <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>PH</mi><mn>3</mn></msub></math> there is no hydrogen bonding present whereas in <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>NH</mi><mn>3</mn></msub></math> There is intermolecular hydrogen bonding present, due to which a lot of energy is required to break these bonds. So, the boiling point of <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>NH</mi><mn>3</mn></msub></math> increases.
Hence, the correct option is (1).
 
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Why does have a lower boiling point than have a lower boiling point than ?