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Width of river is 30m , river velocity is 4 m/s and rowing velocity of boat man is 5 m/s with respect to river.
Match the statements in column I with corresponding results in Column II.
Column I Column II
A Shortest time (in s) p 143
B boat velocity with respect to ground (m/s) in shortest time in case q 10
C Direction of $V_{b r}$ with respect to river to get shortest path (in degree) r $\sqrt{41}$
D Time taken by boat to cross the river in shortest path (in Sec) s 6

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$A \to p; B \to q; C \to r; D \to s$

$A \to s; B \to r; C \to p; D \to q$

$A \to r; B \to q; C \to p; D \to s$

$A \to q; B \to r; C \to q; D \to p$

answer is B.

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Detailed Solution

$\begin{array}{l} W = 30 \\ V_{r} = 4 m / s \\ V_{B r} = 5 m / s \end{array} t_{\min} = \frac{w}{5} = \frac{30}{5} = 6 V_{b} = \sqrt{{V_{r}}^{2} + {V_{B r}}^{2}} = \sqrt{16 + 25} = \sqrt{41}$

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