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Q.

Wires 1 and 2 carrying currents i1 and i2 respectively are inclined at an angleθ to each other. What is the force on a small element dl of wire 2 at a distance r from wire 1 due to magnetic field of wire l

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a

μ04πri1i2dl[1+cosθ]

b

μ02πri1i2dlsinθ

c

μ02πri1i2dlcosθ

d

μ04πri1i2dlsinθ

answer is C.

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Detailed Solution

Length of the component dl which is parallel to wire (i) is l=dlcosθ

Force acting on it is

F=μ02π=i1i2lr=μ02πri1i2(dlcosθ)

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