Wires W1 and W2 are made of same material having the breaking stress of 1.25×109 N/m2 . W1 and W2 have cross-sectional area of 8×10-7 m2 and 4×10-7m2, respectively. Masses of 20 kg and 10 kg hang from them as shown in the figure. The maximum mass that can be placed in the pan without breaking the wires is ____kg. (Use g=10m/s2)

From the question,BS1=T1max8×10-7T1max=8×1.25×100=1000NBS2=T2max4×10-7T2max=4×1.25×100=500N⇒m=500-10010=40kgHence the correct answer is 40Kg.

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Wires W₁ and W₂ are made of same material having the breaking stress of $1.25 \times 10^{9}$ N/m² . W₁ and W₂ have cross-sectional area of $8 \times 10^{- 7} m^{2}$ and $4 \times 10^{- 7} m^{2},$ respectively. Masses of 20 kg and 10 kg hang from them as shown in the figure. The maximum mass that can be placed in the pan without breaking the wires is $____kg . (Use g = 10 m / s^{2})$

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answer is 40.

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Detailed Solution

From the question,

${BS}_{1} = \frac{T_{1 \max}}{8 \times 10^{- 7}}$

$T_{1 \max} = 8 \times 1.25 \times 100 = 1000 N$

${BS}_{2} = \frac{T_{2 \max}}{4 \times 10^{- 7}}$

$T_{2 \max} = 4 \times 1.25 \times 100 = 500 N$

$\Rightarrow m = \frac{500 - 100}{10} = 40 kg$

Hence the correct answer is 40Kg.

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