Wires W1 and W2 are made of same material having the breaking stress of 1.25 x 109N/m2. W1 and W2 have cross-sectional area of 8 x 10-7 m2 and 4 x 10-7 m2, respectively. Masses of 20kg and 10kg hang from them as shown in the figure. The maximum mass that can be placed in the pan without breaking the wires is ___kg. (Use g = 10m/s2).

Let m be mass that can be placed in the pan. For wire W1 stress = Maximum weigth Area =(m+30)g8×10−7⇒m+30g=1.25×109×8×10−7⇒m+30=100⇒m=70kgFor wire W2Stress = (m+10)g4×10−7=1.25×109⇒m+10=50⇒m=40kgMaximum mass that can be placed = 40 kg.

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Wires W₁ and W₂ are made of same material having the breaking stress of 1.25 x 10⁹N/m². W₁ and W₂ have cross-sectional area of 8 x 10^-7 m² and 4 x 10^-7 m², respectively. Masses of 20kg and 10kg hang from them as shown in the figure. The maximum mass that can be placed in the pan without breaking the wires is ___kg. (Use g = 10m/s²).

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answer is 40.

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Detailed Solution

Let m be mass that can be placed in the pan. For wire
$\begin{array}{l} W_{1} stress = \frac{Maximum weigth}{Area} = \frac{(m + 30) g}{8 \times 10^{- 7}} \\ \Rightarrow (m + 30) g = 1.25 \times 10^{9} \times 8 \times 10^{- 7} \\ \Rightarrow m + 30 = 100 \Rightarrow m = 70 kg \end{array}$
For wire W₂
Stress = $\frac{(m + 10) g}{4 \times 10^{- 7}} = 1.25 \times 10^{9} \Rightarrow m + 10 = 50 \Rightarrow m = 40 kg$
Maximum mass that can be placed = 40 kg.