With the help of a graph of the equations x – y + 1 = 0 and 3x + 2y – 12 = 0, find the coordinates of the vertices of the triangle formed by these lines.

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A (2,3), B (-1,2) and C (4,1)

A (2,3), B (-1,0) and C (4,0)

A (2,1), B (-1,5) and C (4,0)

A (2,3), B (-1,3) and C (4,5)

answer is B.

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Detailed Solution

Given two equations are x – y + 1 = 0 and 3x + 2y – 12 = 0.
According to the question,
x - y + 1= 0
x – y = -1
y = x + 1               ------- 1
Other equation is,
3x + 2y – 12 = 0
3x + 2y = 12

y = 12 − 3 x 2

------- 2
Now, putting the value of x = 0 and x = 1 for equation (1) and x = 0 and x = 2 for equation (2) and finding value of y for both the equations:
Question Image

From the graph, we can observe the vertices of triangle are
A (2,3), B (-1,0) and C (4,0).
Hence, option 2 is correct.

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