Within each pair of elements F & Cl, S & Se,
and Li & Na, respectively, the element that
release more energy upon an electron gain
are:

We know that as we move down the group electron affinity decreases due to increasing size. So, the electron affinity of S Se as they both belongs to group3 and  similarly $\mathrm{Li}>\mathrm{Na}$ they both belong to group 1, also energy release will also be more. 

F and CI both belong to the same group 17, but in this case there is an exception, $\mathrm{Cl}>\mathrm{F}$. It is due to the small size of the F atom where the incoming electron faces high electron-electron repulsion. So, the energy release will be more in C.

Hence, option(d) is correct.