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Q.

Without using trigonometric tables what will be the value of   3cos 43 ° sin 47 ° 2 cos 37 ° cosec 53 ° tan 5 ° tan 25 ° tan 45 ° tan 65 ° tan 85 °  ?


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a

7

b

8

c

9

d

6 

answer is B.

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Detailed Solution

Given that,
3cos 43 ° sin 47 ° 2 cos 37 ° cosec 53 ° tan 5 ° tan 25 ° tan 65 ° tan 85 °  
We use,
cosecθ= 1 sinθ sin( 90 ° θ)=cosθ cos( 90 ° θ)=sinθ tan( 90 ° θ)=cotθ tanθcotθ=1  
We get,
= 3cos 43 ° sin (9043) ° 2 cos (9053) ° 1 sin 53 ° tan (9085) ° tan (9065) ° tan 65 ° tan 85 °   = 3cos 43 ° cos 43 ° 2 sin 53 ° 1 sin 53 ° cot 85 ° cot 65 ° tan 65 ° tan 85 °   = 3 2 1 cot 85 ° tan 85 ° cot 65 ° tan 65 °   =91   =8  
Thus the value of 3cos 43 ° sin 47 ° 2 cos 37 ° cosec 53 ° tan 5 ° tan 25 ° tan 65 ° tan 85 °   will be 8  .
Therefore the correct option is 2.
 
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