Q.

Wooden wedge of mass and inclination angle α  rests on a smooth floor. A block of mass is kept on wedge. A force is applied on the wedge as shown in figure, such that a block remains stationary with respect to wedge. The magnitude of force is

 

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a

(M+m)gcosecα

b

gtanα

c

mgcosα

d

(M+m)gtanα

answer is A.

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Detailed Solution

Since, P = (M+m)a

Considering the observer on the block, the block will be at rest w.r.t that observer

 Now as in free body diagram of block,

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macosα=mgsinα

            a=gsinαcosα=gtanα

 P=(M+m)g  tanα

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