Q.


Work done in an adiabatic process between a given pair of end states depends on A. The end states only.


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a

The end states only

b

Particular adiabatic process

c

Mass of the system

d

None of the above 

answer is A.

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Detailed Solution

Concept- End states of a system are dictated by the system's internal energy. There is no heat transmission in an adiabatic system. As a result, the dQ will be zero.
Formula used: Question Image, where Question Image is the heat energy, Question Image is the work done and dU is the internal energy.
The internal energy levels at such states can be used to determine the end states. In the case of a system S, heat energy (dQ) can be employed to do work (dW) or to store energy as potential energy (dU)
Question ImageThe interesting part is that dQ will be 0 for an adiabatic process. As a result, the work done in an adiabatic process is solely determined by the internal energy. End states, in other words. As a result, A is the correct answer.
Further information:
In a real-world context, it is difficult to construct an adiabatic system. Because thermal isolation is difficult to establish. As a result, the adiabatic process is an ideal instance. Some cases, however, can be approximated as an adiabatic process. The scenarios are as follows: relatively well thermally isolated systems, a quick process with no time for heat to escape or enter, and a very large system.
We can derive the adiabatic process equation.
We can write the first law of thermodynamics as follows:
Question ImageFor an adiabatic process, d Q will be zero.
Question ImageWhere,
Question ImageQuestion ImageQuestion Image is the pressure, Question Image is the change in volume, Question Image is the specific heat at constant volume and dT is the change in temperature.
Question Image_______(1)
Now we can use the ideal gas equation.
Question ImageAfter differentiating the ideal gas equation, we can write as,
Question Image__________(2)
Substitute this equation into equation(1)
Question ImageDivide this equation with Question ImageQuestion ImageWe can integrate this equation,
Question Image, here Question Image known as adiabatic index and Question Image is a constant.
We can write this equation as,
Question ImageHence, the correct answer is option 1.
 
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