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Q.

Work done in placing a charge of 8×10-18 C on a condenser of capacity 100 μF is

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a

16×10-32 J

b

31×10-26 J

c

64x10-32 J

d

32×10-32 J

answer is C.

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Detailed Solution

Here, q=8×10-18C,C=100μF=10-4 F

Potential, V=qC=8×10-1810-4=8×10-14 V

Energy stored in the capacitor =12qV=12×8×10-18×8×10-14

                   =32×10-32 J

But work done = 64 x10-32  joule

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