Workdone during this cyclic process, starting from A is ......., q is .......

AB is isobaric process

BC is isochoric process

AC is isothermal process 

W = ${\mathrm{w}}_{\mathrm{AB}}+{\mathrm{w}}_{\mathrm{BC}}+{\mathrm{w}}_{\mathrm{AC}}$

W=$-\mathrm{P}∆\mathrm{V}+0+(2.303\mathrm{nRTlog}\frac{{\mathrm{V}}_{\mathrm{final}}}{{\mathrm{V}}_{\mathrm{initial}}})$

W=$-1(40-20)+0+2.303\mathrm{pvlog}\frac{40}{20}$

W=$-1(40-20)+0+2.303(1\times 20)\log \frac{40}{20}$

W=-20+13.87 = - 6.13 lit -atm X 101.3 J/lit-atm = -620.9 J

since it is cyclic process $∆\mathrm{E}$ = 0

From first law of thermodynamics q = -w = 620.9 J