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Write the equation of an alternating emf of 120V, and its frequency 60Hz

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$e = (169.7 \sin 120 π t) v o l t$

$e = (143.7 \sin 150 π t) v o l t$

$e = (152.7 \sin 110 π t) v o l t$

$e = (156.7 \sin 130 π t) v o l t$

answer is A.

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Detailed Solution

$e = e_{0} \sin ω t; e = e_{r m s} \sqrt{2} \sin 2 π f t$

$e = 169.7 \sin 120 π t$ $= 120 \sqrt{2} \sin 120 π t$ .

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