Write a Pythagorean triplet whose one member is. 

(i) 6 

(ii) 14 

(iii) 16 

(iv) 18

The Pythagorean triplet can be formed by the numbers 2m , m² -1 , m²+1

( i) consider,

2 m = 6

m = 3

Substitute m = 3 in 2m , m² -1 , m²+1

Here, 

m² -1  = 9-1 = 8

 m²+1 = 9 +1 = 10

The Pythagorean triplet is 6, 8, 10

(ii) Consider,

2 m = 14

m = 7

Substitute m = 7 in 2m , m² -1 , m²+1

Here, 

m² -1  = 49-1 = 48

 m²+1 = 49 +1 = 50

The Pythagorean triplet is 14, 48, 50

(iii) Consider,

2 m = 16

m = 8

Substitute m = 8 in 2m , m² -1 , m²+1

Here, 

m² -1  = 64-1 = 63

 m²+1 = 64 +1 = 65

The Pythagorean triplet is 16, 63, 65

(iv) Consider,

2 m = 18

m = 9

Substitute m = 9 in 2m , m² -1 , m²+1

Here, 

m² -1  = 81-1 = 80

 m²+1 = 81 +1 = 82

The Pythagorean triplet is 18, 80, 82