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Write two solutions of the form $x = 0, y = a$ and $x = b, y = 0$ for each of the following equations :

i) $5 x - 2 y = 10$

ii) $- 4 x + 3 y = 12$

iii) $2 x + 3 y = 24$

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(0,−5) and (2,0) ,(0,4) and (−3,0) ,(0,8) and (12,0)

(0,8) and (12,0) ,(0,4) and (−3,0) ,(0,−5) and (2,0)

(0,−5) and (2,0) ,(0,8) and (12,0) ,(0,4) and (−3,0)

None of these

answer is A.

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Detailed Solution

Concept: To find two solutions of the given equation, first we will put the value of x =0 and get the value of y and second time we will put the value of y =0 and get the value of x.
(i)

5 x - 2 y = 10

x = 0

5 (0) - 2 (y) = 10

⇒

y = - 5

y = 0

5 (x) - 2 (0) = 10

5 x = 10

\Rightarrow x = 2

Two solutions are (0,−5) and (2,0)
(ii)

- 4 x + 3 y = 24

x = 0

3 y = 12 \Rightarrow y = 4

Iif

y = 0

- 4 x = 12 \Rightarrow x = - 3

Two solution are (0,4) and (−3,0)
(iii)

2 x + 3 y = 24

x = 0

3 y = 24 \Rightarrow y = 8

y = 0

2 x = 24 \Rightarrow x = 12

Hence, the correct option is 1.

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