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Q.

x = 4 and y = 0 are solution of

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a

2x + 2y = 8

4x + 2y = 6

b

Both A & B are correct

c

2x + 2y = 8

4x - 2y = 16

d

x + y = 4

2x - y = 8

answer is D.

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Detailed Solution

detailed_solution_thumbnail

For option one:  

x + y = 4

x = 4 & y = 0 gives L.H.S = 4 + 0 = 4 = R.H.S

2x - y = 8

x = 4 & y = 0 gives L.H.S = 2(4) - 0 = 8 = R.H.S

For option two: 

2x + 2y = 8

x = 4 & y = 0 gives L.H.S = 2(4) + 2(0) = 8 = R.H.S

4x - 2y = 16

x = 4 & y = 0 gives L.H.S = 4(4) - 2(0) = 16 = R.H.S

Therefore, both A & B are correct.

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