x-1 is a factor of $4x^2-9x-6$. 

According to factor theorem, x-a is a factor of p(x) if p(a) = 0. 

Therefore x-1 is a factor of $4x^2-9x-6$ is a factor if p(1)=0. 

p(1) = 4(1)2-9(1)-6 = 4 – 9 – 6 

= -11 ≠ 0 

Therefore, we can say that x-1 is not a factor of $4x^2-9x-6$.