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Q.

(x11c1x2+11c2x311c3x4+.....11c11x12)dx=

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a

(1x)1313(1x)1212+c

b

(1x)1212(1x)1313+c

c

(1x)1212(1x)1111+c

d

(1x)1111(1x)1212+c

answer is B.

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Detailed Solution

given : x(1x)11dx
=1(1x)(1x)11dx=(1x)11(1x)12dx=(1x)1212+(1x)1313+c

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