$\mathrm{X}-1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^1$ In the above x element electronic configuration to get octet electronic configuration x loses how many electrons _____

Electronic configuration of element X is $1{\mathrm{s}}^{2}2{\mathrm{s}}^{2}2{\mathrm{p}}^{6}3{\mathrm{s}}^1$.In order to get stable octet electronic configuration.$\left({\mathrm{ns}}^2{\mathrm{np}}^6\right)$ the element ‘X’ must lose one electron (form 3s orbital) $\mathrm{X}\to \mathrm{Octet}+{\mathrm{e}}^{-}$