$$\begin{gathered} {\text{X+3H}}_2\mathrm{O}\to \mathrm{Y}+6\mathrm{HF} \\ \mathrm{X}+3{\mathrm{H}}_2\mathrm{O}\to \mathrm{Z}+2\mathrm{HF} \end{gathered}$$
If X is xenon hexafluoride, then correct statement?

$\begin{array}{l}{\mathrm{XeF}}_6+3{\mathrm{H}}_2\mathrm{O}\to \underset{\mathrm{Y}}{{\mathrm{XeO}}_3}+6\mathrm{HF}\\ {\mathrm{XeF}}_6+{\mathrm{H}}_2\mathrm{O}\to \underset{\mathrm{Z}}{{\mathrm{XeOF}}_4}+2\mathrm{HF}\end{array}$

Both Y and Z have one lone pair of electrons on the central atom (Xe). 

Partial hydrolysis of XeF₆ gives oxyfluorides, XeOF₄ and XeO₂F₂.

’X’ acts as fluoride ion Acceptor when it reacts with alkali metal fluoride.

XeF₆ + MF → M⁺ [XeF₇]^– (M = Na, K, Rb or Cs)