‘x’ grams of 50 % pure potassium chlorate liberates 0.3 moles of oxygen on thermal decomposition. ‘x’ grams of pure H2SO4 require _____grams of NaOH for complete neutralization(MW of potassium chlorate = 122.5)

2KClO3⟶Δ2KCl+3O2 2(122.5g)3moles?0.3moles WKClO3(100% pure )=24.5gWKClO3(50% pure )=49gH2SO4+2NaOH→Na2SO4+2H2O98g 2(40g)49g 40g

‘x’ grams of 50 % pure potassium chlorate liberates 0.3 moles of oxygen on thermal decomposition. ‘x’ grams of pure H2SO4 require _____grams of NaOH for complete neutralization(MW of potassium chlorate = 122.5)

2KClO3⟶Δ2KCl+3O2 2(122.5g)3moles?0.3moles WKClO3(100% pure )=24.5gWKClO3(50% pure )=49gH2SO4+2NaOH→Na2SO4+2H2O98g 2(40g)49g 40g

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

‘x’ grams of 50 % pure potassium chlorate liberates 0.3 moles of oxygen on thermal decomposition. ‘x’ grams of pure H₂SO₄ require _____grams of NaOH for complete neutralization
(MW of potassium chlorate = 122.5)

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

20 g

40 g

60 g

50 g

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{ll} 2 {KClO}_{3} \overset{Δ}{⟶} 2 KCl + 3 O_{2} \\ 2 (122.5 g) & 3 moles \\ ? & 0.3 moles \end{array} \begin{array}{l} W_{{KClO}_{3}} (100 % pure) = 24.5 g \\ W_{{KClO}_{3}} (50 % pure) = 49 g \\ H_{2} {SO}_{4} + 2 NaOH \to {Na}_{2} {SO}_{4} + 2 H_{2} O \\ 98 g 2 (40 g) \\ 49 g 40 g \end{array}$