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‘X’ grams of sodium bicarbonate liberated sufficient carbon dioxide which can completely oxidize 6 grams of coke. Value of ‘X’ is

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126 g

42 g

84 g

21 g

answer is D.

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Detailed Solution

$\begin{array}{l} {CO}_{2} (g) + C (s) \to 2 CO (g) \\ 1 mole 12 g \\ 0.5 moles 6 g \\ 2 {NaHCO}_{3} (s) \to {Na}_{2} {CO}_{3} (s) + H_{2} O (g) + {CO}_{2} (g) \\ (2 \times 84) g 1 mole \\ ' X' g 0.5 moles \\ X = 84 g \end{array}$

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