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‘X’ grams sodium bicarbonate liberated sufficient carbondioxide which can completely oxidize 36 grams of coke. Value of ‘X’ is

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252 g

336 g

168 g

504 g

answer is D.

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Detailed Solution

$\begin{array}{l} {CO}_{2} (g) + C (s) \to 2 CO (g) \\ 1 mole 12 g \\ 3 moles 36 g \\ 2 {NaHCO}_{3} (s) \to {Na}_{2} {CO}_{3} (s) + H_{2} O (g) + {CO}_{2} (g) \\ (2 \times 84) g 1 mole \\ ' X' g 3 moles \\ X = 504 g \end{array}$

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