‘X’ in this reaction is

A) LiAlH₄            B) NaBH₄            C) Zn-Hg/Conc.HCl                 D) N₂H₄/KOH, glycol

E) HI + Red $\mathrm{P}/∆$

X = Zn-Hg/Conc.HCl …… Clemmenson's reduction

= N₂H₄/KOH, glycol …… Wolf - Kishner reduction

$=\mathrm{HI} + \mathrm{P}/∆$

LiAlH₄ and NaBH₄ reduces ketones to 2^o alcohols.