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Q.

X mL of a 60% w/w alcohol by weight (d = 0.6 gm/mL) must be used to prepare 200 mL of 12% alcohol by weight (d = 0.9 gm/mL). Then the value of X will be:

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a

20

b

40

c

60

d

80

answer is C.

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Detailed Solution

The value of X can be calculated as,

X×0.6×60100 =200×0.9×12100

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