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Q.

X mL of a 60% w/w alcohol by weight (d = 0.6 gm/mL) must be used to prepare 200 mL of 12% alcohol by weight (d = 0.9 gm/mL). Then the value of X will be:

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a

60

b

20

c

40

d

80

answer is C.

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Detailed Solution

The value of X can be calculated as,

$X \times 0.6 \times \frac{60}{100} = 200 \times 0.9 \times \frac{12}{100}$

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