x mol of $Fe{C}_2{O}_4$ on reaction with $A{l}_2{\left(C{r}_2{O}_7\right)}_3$  requires 500 ml of 0.4M of it. Select the correct statement(s)

n – factor of  $A{l}_2{\left(C{r}_2{O}_7\right)}_3$  is 6

n – factor of  $A{l}_2{\left(C{r}_2{O}_7\right)}_3$ is 18

Moles of x, which react with $A{l}_2{\left(C{r}_2{O}_7\right)}_3$  is 0.2 

Moles of x, which react with $A{l}_2{\left(C{r}_2{O}_7\right)}_3$  is 0.4