X mole of KCl and Y mole of BaCl2 are both dissolved in 1kg of water. Givenx = y = 0.1 and Kf = 1.85 k molal-1 , what is the observed range of ∆Tf If the ratio of x to y is varied

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X mole of KCl and Y mole of ${BaCl}_{2}$ are both dissolved in 1kg of water. Givenx = y = 0.1 and Kf = 1.85 k ${molal}^{- 1}$ , what is the observed range of $∆ T_{f}$ If the ratio of x to y is varied

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0.185 to 0.93

0.37 to 0.93

0.37 to 0.55

0.56 to 0.93

answer is B.

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Detailed Solution

$∆ T_{f_{1}} = 0.1 \times 1.85 = 0.185$

$∆ T_{f_{1}} = 0.1 \times 1.85 \times 5 = 0.93$

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