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Q.

‘x’ moles of a monoacidic base are dissolved in one liter of a solution. The pH of the solution is

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a

−log x

b

14 − log x

c

14 + log x

d

−log(14 − x)

answer is C.

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Detailed Solution

POH=-log10OH-=-log10x

pH + pOH = 14 

pH = 14 − (pOH)

=14--log10x=14+log10x

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‘x’ moles of a monoacidic base are dissolved in one liter of a solution. The pH of the solution is