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Q.

‘x’ moles of a monoacidic base are dissolved in one liter of a solution. The pH of the solution is

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a

14 + log x

b

−log x

c

14 − log x

d

−log(14 − x)

answer is C.

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Detailed Solution

$POH = - \log_{10}^{[{OH}^{-}]} = - \log_{10}^{x}$

pH + pOH = 14

pH = 14 − (pOH)

$= 14 - (- \log_{10}^{x}) = 14 + \log_{10}^{x}$

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