X varies directly as cube root of y. Given X is 12, when Y is 8. Find X, when Y is 27.

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Detailed Solution

$\begin{array}{l} X α \sqrt[3]{y} \\ X = 12, when Y = 8 \\ X α \sqrt[3]{y} \\ X = k . y^{\frac{1}{3}} \\ 12 = k {(2^{3})}^{\frac{1}{3}} \\ k = 6 \\ Find X, when Y = 27 \\ X = k {(27)}^{\frac{1}{3}} \\ X = 6 \times 3 \\ X = 18 \end{array}$

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