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$|\begin{array}{ccc} x + y & 0 & 0 \\ 0 & x - y & 0 \\ 0 & 0 & x^{2} + y^{2} \end{array}| =$

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x⁴-y⁴

x⁴+y⁴

x⁹-y⁸

x⁶-y⁶

answer is A.

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Detailed Solution

det = (x+y)(x-y)(x²+y²)=x⁴-y⁴

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