x=1−y1+y then dydx =

x=1−y1+y⇒1+x1−x=1+y+1−y1+y−1+y=1y⇒y=1−x1+x2dydx=21−x1+x×1+x−1−1−x11+x2=21−x1+x3−1−x−1+x=4x−11+x3

x=1−y1+y then dydx =

x=1−y1+y⇒1+x1−x=1+y+1−y1+y−1+y=1y⇒y=1−x1+x2dydx=21−x1+x×1+x−1−1−x11+x2=21−x1+x3−1−x−1+x=4x−11+x3

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

$x = \frac{1 - \sqrt{y}}{1 + \sqrt{y}} t h e n \frac{d y}{d x} =$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$\frac{(x - 1)}{{(1 + x)}^{3}}$

$\frac{4}{{(x + 1)}^{3}}$

$\frac{4}{{(x + 1)}^{2}}$

$\frac{4 (x - 1)}{{(1 + x)}^{3}}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$x = \frac{1 - \sqrt{y}}{1 + \sqrt{y}} \Rightarrow \frac{1 + x}{1 - x} = \frac{1 + \sqrt{y} + 1 - \sqrt{y}}{1 + \sqrt{y} - 1 + \sqrt{y}} = \frac{1}{\sqrt{y}} \Rightarrow y = {[\frac{1 - x}{1 + x}]}^{2}$

$\frac{d y}{d x} = 2 [\frac{1 - x}{1 + x}] \times \frac{(1 + x) (- 1) - (1 - x) 1}{{(1 + x)}^{2}} = \frac{2 (1 - x)}{{(1 + x)}^{3}} (- 1 - x - 1 + x) = \frac{4 (x - 1)}{{(1 + x)}^{3}}$