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Q.

(x7m+x2m+xm)(2x6m+7xm+14)1mdx=

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a

2x7m+7x2m+xmm+1m1m+1

b

114m+12x7m+7x2m+14xmm+1m

c

x7m+x2m+xmm+1

d

2x7m+7x2m+xmm+1m

answer is B.

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Detailed Solution

I=(x7m+x2m+xm)(2x6m+7xm+14)1mdx

=(x7m-1+x2m-1+xm-1).x. 2.x6m+7xm+141mdx

=(x7m-1+x2m-1+xm-1).xm2.x6m+7xm+14 1mdx

=(x7m-1+x2m-1+xm-1)2x7m+7x2m+14xm 1mdx

Put 2x7+7x2m+14xm=t

14x7m-1+14mx2m-1+14mxm-1dx=dt x7m-1+x2m-1+xm-1dx=dt14m I=t1/m dt14m =114m t1m+11m+1+C =114m+12x7m+7x2m+14xm1+mm

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∫(x7m+x2m+xm)(2x6m+7xm+14)1mdx=