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Q.

xa2+b2xaba+bxb2+c2xbcb+cxc2+a2xaca+c=

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a

1

b

1

c

4

d

2

answer is A.

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Detailed Solution

=(xa2+b2ab)a+b.(xb2+c2bc)b+c.(xc2+a2ac)a+c

=x(a+b)(a2+b2ab)×x(b+c)(b2+c2bc)×x(a+c)(a2+c2ac)

=xa3b3×xb3c3×xc3a3

=x0

=1

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