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$X + C + {Cl}_{2} \frac{High temperature}{of about 1000 K} ⟶ Y + CO$
$Y + 2 H_{2} O ⟶ Z + 2 HCl$
Compound Y is found in polymeric chain structure and is an electron deficient molecule Y must be:

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$BeO$

${BeH}_{2}$

${BeCl}_{2}$

${AlCl}_{3}$

answer is B.

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Detailed Solution

The reaction is,

$BeO + C + {Cl}_{2} \frac{Hightemperature}{ofabout100K} {BeCl}_{2} + CO$

${BeCl}_{2} + 2 H_{2} O \to Be (OH)_{2} + 2 HCl$

And only Be produces polymer among all alkali metals.

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