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XeF₂ donates F^- when reacts with (X) and accepts F^- when reacts with (Y). X and Y are respectively

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RbF, CsF

PtF₅,PtF₅

KF,AsF₅

SbF₅,NaF

answer is C.

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Detailed Solution

X must be acceptor and Y must be donor . Acceptor should have vacant orbital to accept electron pair from flouride ion of XeF₂

Electron pair of F^- of donor is accepted by vacant orbital of Xe of XeF₂

X = MF₅ ( M = P,As,Sb,Bi,Pt etc)

Y = MF ( M = Na ,K, Rb,Cs etc)

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