$Xe{F}_4$  is square planar while  $Xe{F}_6$ has a distorted octahedral structure what is the correct explanation for this observation? 

Both molecules have one lone pair of electrons

Both molecules have two lone pair of electrons

$Xe{F}_4$  has two lone pair electrons on $Xe:Xe{F}_6$  has one lone pair of electrons on Xe

$Xe{F}_4$  doesn’t have any lone pair of electrons
 $Xe{F}_6$ has one lone pair of electrons on $Xe$ atom