$X e F_{4}$ is square planar while $X e F_{6}$ has a distorted octahedral structure what is the correct explanation for this observation?

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Both molecules have one lone pair of electrons

Both molecules have two lone pair of electrons

$X e F_{4}$ has two lone pair electrons on $X e : X e F_{6}$ has one lone pair of electrons on Xe

$X e F_{4}$ doesn’t have any lone pair of electrons
$X e F_{6}$ has one lone pair of electrons on $X e$ atom

answer is D.

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Detailed Solution

$X e F_{4}$ has two lone pair of electrons on $X e (s p^{3} d^{2})$
$X e F_{6}$ has one lone pair of electrons on $X e (s p^{3} d^{3})$

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