XeF₆ on partial hydrolysis gives

When ${\mathrm{XeF}}_6$ reacts with a higher amount of water, it undergoes further hydrolysis to form xenon oxydifluoride ${\mathrm{XeO}}_2{\mathrm{F}}_{2 }$ and xenon oxytetrafluoride $2{\mathrm{XeOF}}_4$ according to the following equation:

${\mathrm{XeF}}_6 + 4{\mathrm{H}}_2\mathrm{O} \to {\mathrm{XeO}}_2{\mathrm{F}}_{2 }+ 2{\mathrm{XeOF}}_4 + 6\mathrm{HCl}$

The ${\mathrm{XeF}}_6$ molecule reacts with four water molecules to form one molecule of ${\mathrm{XeO}}_2{\mathrm{F}}_{2 }$, two molecules of $2{\mathrm{XeOF}}_4$, and six molecules of hydrochloric acid ($\mathrm{HF}$).