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${XeF}_{6}$ on partial hydrolysis with water produces a compound, ‘X’. The same compound ‘X’ is formed when ${XeF}_{6}$ reacts with silica. The compound ‘X’ is:

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$X e F_{2}$

$X e F_{4}$

$X e O F_{4}$

$X e O_{3}$

answer is C.

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Detailed Solution

Partial hydrolysis of XeF₆ gives XeOF₄ (compound X)
XeF₆+ H₂O → XeOF₄ (X)+ 2HF

XeF₆ reacts with silica SiO₂ to form XeOF₄ (compound X)
2XeF₆ + SiO₂→2XeOF₄ (X)+ SiF₄

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