${XeF}_{6}$ on complete hydrolysis gives:

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${XeO}_{3}$

${XeO}_{4}$

${XeO}_{2}$

$Xe$

answer is C.

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Detailed Solution

One of the three binary fluorides that the xenon forms is $XeF6$ . $XeF6$ undergoes complete hydrolysis to yield ${XeO}_{3}$ , or xenon trioxide. The xenon trioxide in question is extremely explosive and functions well in solutions as an oxidizer.

${XeF}_{6} + 3 H_{2} O ⟶ {XeO}_{3} + 6 HF$

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