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Q.

${XeF}_{6}$ on complete hydrolysis gives a compound ‘X’ The oxidation state of ‘Xe’ in the compound X is

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answer is 6.

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Detailed Solution

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${XeF}_{6} \to + 3 H_{2} O \to {XeO}_{3} + 6 HF In {XeO}_{3} \to O . S of Xe is \to + 6$

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