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Q.

Xenon crystallizes in face centre cubic lattice and the edge of the unit cell is 620 pm. then the radius of xenon-atom is

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a

265.5 pm

b

219.25 pm

c

536.94 pm

d

438.5 pm

answer is B.

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Detailed Solution

For fcc lattice

$4 r = \sqrt{2} a$ where a = 620 pm

or, $r = \frac{1}{2 \sqrt{2}} \times a$

$= \frac{1}{2 \sqrt{2}} \times 620 p m$

$= 219.20 p m$

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