Xenon difluoride reacts ${\mathrm{PF}}_5$, they give which pair of ions

$\left[{\mathrm{XeF}}_2\right]+\left[{\mathrm{PF}}_5\right]\to {\left[\mathrm{XeF}\right]}^{+}{\left[{\mathrm{PF}}_6\right]}^{-}$

Xenon fluorides are obtained when xenon difluoride reacts with ${\mathrm{PF}}_5$ because ${\mathrm{PF}}_5$ is known to be a fluoride ion acceptor hence, it produces cationic species.