Xg of Ag was dissolved in HNO₃ and the solution was treated with excess of NaCl when 2.87g of AgCl was precipitated. The value of X is

${\mathrm{Ag}}^{+}+{\mathrm{Cl}}^{-}⟶\mathrm{AgCl}$

Atomic mass of Ag=108 g

Atomic mass of Cl=35.5 g

Molecular mass of AgCl=143.5 g

143.5 g AgCl is obtained from 108 g Ag

2.87 g AgCl is obtained from = $\frac{108\times 2.87}{143.5}=2.16 \mathrm{g}$