X→HOClY If Y is 2-chloroethanol, then X is

C2H4.Concept: The compound Y, 2-chloroethanol, is formed when a molecule reacts with hypochlorous acid (HOCl). This reaction occurs through the addition of HOCl to an alkene, where the -OH and -Cl groups add to adjacent carbon atoms. The starting molecule, X, must therefore have a double bond to allow this reaction.2-chloroethanol has the structure:CH2-Cl-CH2-OHThis indicates that the -Cl and -OH groups are attached to adjacent carbon atoms. The starting molecule must be ethene (C2H4) because it is the simplest alkene with a double bond.Reaction:CH2=CH2 + HOCl → CH2-Cl-CH2-OHHere, HOCl adds across the double bond of ethene, resulting in 2-chloroethanol.The correct option is c. C2H4.

X→HOClY If Y is 2-chloroethanol, then X is

C2H4.Concept: The compound Y, 2-chloroethanol, is formed when a molecule reacts with hypochlorous acid (HOCl). This reaction occurs through the addition of HOCl to an alkene, where the -OH and -Cl groups add to adjacent carbon atoms. The starting molecule, X, must therefore have a double bond to allow this reaction.2-chloroethanol has the structure:CH2-Cl-CH2-OHThis indicates that the -Cl and -OH groups are attached to adjacent carbon atoms. The starting molecule must be ethene (C2H4) because it is the simplest alkene with a double bond.Reaction:CH2=CH2 + HOCl → CH2-Cl-CH2-OHHere, HOCl adds across the double bond of ethene, resulting in 2-chloroethanol.The correct option is c. C2H4.

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

$X \overset{HOC l}{\to} Y$ If Y is 2-chloroethanol, then X is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$C_{2} H_{6}$

$C_{2} H_{5} {NH}_{2}$

$C_{2} H_{4}$

$C_{2} H_{5} OH$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

C₂H₄.

Concept: The compound Y, 2-chloroethanol, is formed when a molecule reacts with hypochlorous acid (HOCl). This reaction occurs through the addition of HOCl to an alkene, where the -OH and -Cl groups add to adjacent carbon atoms. The starting molecule, X, must therefore have a double bond to allow this reaction.

2-chloroethanol has the structure:

CH₂-Cl-CH₂-OH

This indicates that the -Cl and -OH groups are attached to adjacent carbon atoms. The starting molecule must be ethene (C₂H₄) because it is the simplest alkene with a double bond.

Reaction:

CH₂=CH₂ + HOCl → CH₂-Cl-CH₂-OH

Here, HOCl adds across the double bond of ethene, resulting in 2-chloroethanol.

The correct option is c. C₂H₄.