X→HOClY If Y is 2-chloroethanol, then X is

C2H4.Concept: The compound Y, 2-chloroethanol, is formed when a molecule reacts with hypochlorous acid (HOCl). This reaction occurs through the addition of HOCl to an alkene, where the -OH and -Cl groups add to adjacent carbon atoms. The starting molecule, X, must therefore have a double bond to allow this reaction.2-chloroethanol has the structure:CH2-Cl-CH2-OHThis indicates that the -Cl and -OH groups are attached to adjacent carbon atoms. The starting molecule must be ethene (C2H4) because it is the simplest alkene with a double bond.Reaction:CH2=CH2 + HOCl → CH2-Cl-CH2-OHHere, HOCl adds across the double bond of ethene, resulting in 2-chloroethanol.The correct option is c. C2H4.

X→HOClY If Y is 2-chloroethanol, then X is

C2H4.Concept: The compound Y, 2-chloroethanol, is formed when a molecule reacts with hypochlorous acid (HOCl). This reaction occurs through the addition of HOCl to an alkene, where the -OH and -Cl groups add to adjacent carbon atoms. The starting molecule, X, must therefore have a double bond to allow this reaction.2-chloroethanol has the structure:CH2-Cl-CH2-OHThis indicates that the -Cl and -OH groups are attached to adjacent carbon atoms. The starting molecule must be ethene (C2H4) because it is the simplest alkene with a double bond.Reaction:CH2=CH2 + HOCl → CH2-Cl-CH2-OHHere, HOCl adds across the double bond of ethene, resulting in 2-chloroethanol.The correct option is c. C2H4.

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$X \overset{HOC l}{\to} Y$ If Y is 2-chloroethanol, then X is

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$C_{2} H_{6}$

$C_{2} H_{5} {NH}_{2}$

$C_{2} H_{4}$

$C_{2} H_{5} OH$

answer is C.

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Detailed Solution

C₂H₄.

Concept: The compound Y, 2-chloroethanol, is formed when a molecule reacts with hypochlorous acid (HOCl). This reaction occurs through the addition of HOCl to an alkene, where the -OH and -Cl groups add to adjacent carbon atoms. The starting molecule, X, must therefore have a double bond to allow this reaction.

2-chloroethanol has the structure:

CH₂-Cl-CH₂-OH

This indicates that the -Cl and -OH groups are attached to adjacent carbon atoms. The starting molecule must be ethene (C₂H₄) because it is the simplest alkene with a double bond.

Reaction:

CH₂=CH₂ + HOCl → CH₂-Cl-CH₂-OH

Here, HOCl adds across the double bond of ethene, resulting in 2-chloroethanol.

The correct option is c. C₂H₄.