x=log0.13,y=log0.113 and z=log0.13then the correct statement is

x=log0.13,y=log0.113 and z=log0.13x=log0.11.732, y=log0.10.3, z=log0.13y>x>z

x=log0.13,y=log0.113 and z=log0.13then the correct statement is

x=log0.13,y=log0.113 and z=log0.13x=log0.11.732, y=log0.10.3, z=log0.13y>x>z

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$x = \log_{0.1} \sqrt{3}, y = \log_{0.1} \frac{1}{3} and z = \log_{0.1} 3$ then the correct statement is

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$x > z > y$

$z > x > y$

$x > y > z$

$y > x > z$

answer is B.

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$\begin{array}{l} x = \log_{0.1} \sqrt{3}, y = \log_{0.1} \frac{1}{3} and z = \log_{0.1} 3 \\ x = \log_{0.1} 1.732, y = \log_{0.1} 0.3, z = \log_{0.1} 3 \\ y > x > z \end{array}$

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x=log0.13,y=log0.113 and z=log0.13then the correct statement is

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$x = \log_{0.1} \sqrt{3}, y = \log_{0.1} \frac{1}{3} and z = \log_{0.1} 3$ then the correct statement is