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Q.

X+n belongs to III group. It gives green precipitate (P) with alkali solution.(P) dissolves in NaOH and bromine water to form (Q).Addition of BaCl2 to (Q) gives yellow precipitate.How many electrons are present in X+n ?

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answer is 21.

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Detailed Solution

X+n = Cr+3

number of electrons = 24 - 3 = 21

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