x∈R:2x−1x3+4x2+3x∈R=

=fx=2x−1x3+4x2+3x is defined iff x3+4x2+3x≠0⇒ xx2+4x+3≠0⇒ xx+1x+3≠0⇒ x≠0, −1, −3∴ x∈R−0, −1, −3

x∈R:2x−1x3+4x2+3x∈R=

=fx=2x−1x3+4x2+3x is defined iff x3+4x2+3x≠0⇒ xx2+4x+3≠0⇒ xx+1x+3≠0⇒ x≠0, −1, −3∴ x∈R−0, −1, −3

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

$\{x \in R : \frac{2 x - 1}{x^{3} + 4 x^{2} + 3 x} \in R\} =$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$R - \{0, 1, 3\}$

$R - \{0, - 1, - 3\}$

$R - \{0, - 1, - 3, \frac{1}{2}\}$

$R - \{0\}$

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

= $\begin{array}{l} f (x) = \frac{2 x - 1}{x^{3} + 4 x^{2} + 3 x} i s d e f i n e d i f f x^{3} + 4 x^{2} + 3 x \neq 0 \\ \Rightarrow x (x^{2} + 4 x + 3) \neq 0 \\ \Rightarrow x (x + 1) (x + 3) \neq 0 \\ \Rightarrow x \neq 0, - 1, - 3 \\ ∴ x \in R - \{0, - 1, - 3\} \end{array}$